6x^2+-35x+48=0

Solution for 6x^2+-35x+48=0 equation:

6x^2+-35x+48=0

We add all the numbers together, and all the variables

6x^2-35x=0

a = 6; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·6·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*6}=\frac{70}{12}
=5+5/6
$